14m^2-4m^2=20m+11m

Solution for 14m^2-4m^2=20m+11m equation:

14m^2-4m^2=20m+11m

We move all terms to the left:

14m^2-4m^2-(20m+11m)=0

We add all the numbers together, and all the variables

14m^2-4m^2-(+31m)=0

We add all the numbers together, and all the variables

10m^2-(+31m)=0

We get rid of parentheses

10m^2-31m=0

a = 10; b = -31; c = 0;
Δ = b2-4ac
Δ = -312-4·10·0
Δ = 961
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{961}=31$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-31)-31}{2*10}=\frac{0}{20}
=0
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-31)+31}{2*10}=\frac{62}{20}
=3+1/10
$